A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties:
- The left subtree of a node contains only nodes with keys less than or equal to the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Insert a sequence of numbers into an initially empty binary search tree. Then you are supposed to count the total number of nodes in the lowest 2 levels of the resulting tree.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤1000) which is the size of the input sequence. Then given in the next line are the N integers in [−10001000] which are supposed to be inserted into an initially empty binary search tree.
Output Specification:
For each case, print in one line the numbers of nodes in the lowest 2 levels of the resulting tree in the format:
n1 + n2 = n
where n1
is the number of nodes in the lowest level, n2
is that of the level above, and n
is the sum.
Sample Input:
925 30 42 16 20 20 35 -5 28
Sample Output:
2 + 4 = 6
1 #include2 #include 3 #include 4 #include 5 #include 6 using namespace std; 7 int height; 8 struct node{ 9 int data,h,lvl;10 node* l,*r;11 };12 node* newnode(int x){13 node* root = new node;14 root->data=x;15 root->l=NULL;16 root->r=NULL;17 root->h=1;18 return root;19 }20 int geth(node* root){21 if(root==NULL) return 0;22 return root->h;23 }24 void updateh(node* root){25 root->h = max(geth(root->l),geth(root->r))+1;26 }27 void insert(node* &root,int x){28 if(root==NULL) {29 root=newnode(x);30 return;31 }32 if(x>root->data){33 insert(root->r,x);34 updateh(root);35 }36 else if(x<=root->data){37 insert(root->l,x);38 updateh(root);39 }40 }41 int main(){42 int n;43 scanf("%d",&n);44 node* root = NULL;45 for(int i=0;i h;51 int n1=0,n2=0;52 queue q;53 root->lvl=1;54 q.push(root);55 while(!q.empty()){56 node* now=q.front();57 q.pop();58 //printf("%d %d\n",now->data,now->lvl);59 if(now->l!=NULL){60 now->l->lvl=now->lvl+1;61 q.push(now->l);62 }63 if(now->r!=NULL){64 now->r->lvl=now->lvl+1;65 q.push(now->r);66 }67 if(now->lvl==height)n1++;68 if(now->lvl==height-1)n2++;69 }70 printf("%d + %d = %d",n1,n2,n1+n2);71 }
注意点:二叉搜索树的建立与层序遍历。不过好像做麻烦了,用dfs会更简洁。又好像dfs都不用,可以直接在插入时候加个lvl数组算